b^3-4b^2-45b=0

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Solution for b^3-4b^2-45b=0 equation:


Simplifying
b3 + -4b2 + -45b = 0

Reorder the terms:
-45b + -4b2 + b3 = 0

Solving
-45b + -4b2 + b3 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), 'b'.
b(-45 + -4b + b2) = 0

Factor a trinomial.
b((-5 + -1b)(9 + -1b)) = 0

Subproblem 1

Set the factor 'b' equal to zero and attempt to solve: Simplifying b = 0 Solving b = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b = 0

Subproblem 2

Set the factor '(-5 + -1b)' equal to zero and attempt to solve: Simplifying -5 + -1b = 0 Solving -5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1b = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1b = 0 + 5 -1b = 0 + 5 Combine like terms: 0 + 5 = 5 -1b = 5 Divide each side by '-1'. b = -5 Simplifying b = -5

Subproblem 3

Set the factor '(9 + -1b)' equal to zero and attempt to solve: Simplifying 9 + -1b = 0 Solving 9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1b = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1b = 0 + -9 -1b = 0 + -9 Combine like terms: 0 + -9 = -9 -1b = -9 Divide each side by '-1'. b = 9 Simplifying b = 9

Solution

b = {0, -5, 9}

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